28=t^2-t/2

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Solution for 28=t^2-t/2 equation: 


t in (-oo:+oo)

28 = t^2-(t/2) // - t^2-(t/2)

t/2-t^2+28 = 0

1/2*t-t^2+28 = 0

DELTA = (1/2)^2-(-1*4*28)

DELTA = 449/4

DELTA > 0

t = ((449/4)^(1/2)-1/2)/(-1*2) or t = (-(449/4)^(1/2)-1/2)/(-1*2)

t = ((449/4)^(1/2)-1/2)/(-2) or t = ((449/4)^(1/2)+1/2)/2

t in { ((449/4)^(1/2)-1/2)/(-2), ((449/4)^(1/2)+1/2)/2 }

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